A Water Bug Is Suspended On The Surface Of A Pond By Surface Tension (water Does Not Wet The Legs). The (2024)

Answer:

t = Δa / v

Explanation:

To know which option is not true, we shall fine a relationship between acceleration (a), velocity (v), time (t) and radius (r). This is illustrated below:

Acceleration can simply be defined as the rate of change of velocity with time. Mathematically, it is expressed as shown below:

Acceleration = change in velocity / time

a = Δv / t ..... (1)

But

Δv = v₂ – v₁

Substitute the value of Δv into equation (1)

a = Δv / t

a = v₂ – v₁ / t ....... (2)

From equation (1), make Δv the subject of the equation.

a = Δv / t

Cross multiply

Δv = at .... (3)

From equation (1), make t the subject of the equation.

a = Δv / t

Cross multiply

at = Δv

Divide both side by a

t = Δv /a ...... (4)

From circular motion, centripetal's force is given by:

F = mv²/r

F = ma꜀

Therefore,

ma꜀ = mv²/r

Cancel out m

a꜀ = v²/r

SUMMARY:

a = Δv / t

a = v₂ – v₁ / t

Δv = at

t = Δv /a

a꜀ = v²/r

Considering the options given in question above, t = Δa / v is not a true statement.

Answer:

Option 4

Explanation:

Answer:

The period of this pendulum is [tex]T=1.55\: s[/tex]

Explanation:

The equation of motion of a pendulum is given by:

[tex]\frac{d\theta^{2}}{dt^{2}}+\frac{g}{L}sin(\theta)=0[/tex] (1)

Where:

θ is the angle of motion

g is the gravity at the earth surface (9.81 m/s²)

L is the length of the pendulum (0.6 m)

Now, using equation (1) we can find the square angular frequency (ω), it will be:

[tex]\omega^{2}=\frac{g}{L}[/tex]

[tex]\omega=\sqrt{\frac{g}{L}}[/tex]

Let's recall that the angular frequency is [tex]\omega=\frac{2\pi}{T}[/tex], then the period will be:

[tex]T=\frac{2\pi}{\omega}[/tex]

[tex]T={2\pi}\sqrt{\frac{L}{g}[/tex]

[tex]T=2\pi}\sqrt{\frac{0.6}{9.81}[/tex]

Therefore, the period of this pendulum is [tex]T=1.55\: s[/tex]

I hope it helps you!

Answer:

6.2j

Explanation:

work done=force × displacement

wd=11N×0.56m

wd=6.16N/m~6.2j

Answer:

The current flowing through a resistor at a constant temperature is directly proportional to the potential difference across it. ... This is called Ohm's law.

Explanation:

I Looked It Up. So It May Be Wrong But I Hope This Helps!

Answer:

The current flowing through a resistor at a constant temperature is directly proportional to the potential difference across it. ... This is called Ohm's law.

Answer:

Option B. 28 N

Explanation:

From the question given above, the following data were obtained:

Coefficient of static friction (μ) = 0.35

Normal force (N) = 80 N

Frictional force (F) =?

The coefficient of static friction, frictional force and the normal force are related according to the following equation:

Coefficient of friction = frictional force / normal force

μ = F/N

With the above formula, we can obtain the frictional force as follow:

Coefficient of static friction (μ) = 0.35

Normal force (N) = 80 N

Frictional force (F) =?

μ = F/N

0.35 = F / 80

Cross multiply

F = 0.35 × 80

F = 28 N

Thus the frictional force is 28 N

Answer:

Option B. 28 N

Explanation:

Answer:

okay, So Um,

Explanation:

BTW, There are only 50 points, brainly subtracts half of the points

Answer:

convert thermal energy into mechanical energy

Explanation:

Thermodynamics generally deals with the energy changes in chemical reactions and how its affect or its influence of energy on those changes. It is widely known to be a branch of physics. It deals mainly on heat transfer processes whereby energy in the form of heat is converted into work. It simply covers or the study of energy flow in the world as a whole and the flow relationship to work, heat, the different forms of energy, and entropy.

Thermodynamics is a branch of physics that deals with the study of energy and its transformations in systems, including the transfer of heat and work. The thermodynamic processes that occur in nature convert thermal energy into mechanical energy, lead to a more ordered state, and cannot be reversed.

These processes are governed by the laws of thermodynamics, which describe the behavior of energy in various systems. The conversion of thermal energy into mechanical energy occurs through processes such as combustion, where heat is generated and used to perform work.

Natural processes tend to increase the overall order or organization in a system, known as an increase in entropy. While energy can be converted and transferred, the total energy within a closed system remains constant due to the law of energy conservation.

Therefore, the thermodynamic processes that occur in nature convert thermal energy into mechanical energy, lead to a more ordered state, and cannot be reversed.

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Answer:

Impulse = 0.9408Ns

Explanation:

Impulse is the product of force and time

Impulse = Ft

Given

Force F = mg

F = 12(9.8)

F = 117.6N

Time = 8 * 10^-3 = 0.008s

Get the impulse

Impulse = 117.6*0.008

Impulse = 0.9408Ns

Answer:

due to gravity.

Explanation:

.............

Answer:

how much the atom weights

Explanation:

Answer:

122.735 behind converging lens ; 2.16

Explanation:

Given tgat:

Object distance, u = 29 cm

Image distance, v =

Focal length, f = - 19 (diverging lens)

Mirror formula :

1/u + 1/v = 1/f

1/29 + 1/v = - 1/19

1/v = - 1/19 - 1/29

1/v = −0.087114

v = −11.47916

v = -11.48

Second lens

Object distance :

u = 11.48 + 11 = 22.48 cm

1/v = 1/19 - 1/22.48

1/v = 0.0081475

v = 1 / 0.0081475

v = 122.735 cm

122.735 behind second lens

Magnification, m

m = m1 * m2

m = - v / u

Lens1 :

m1 = -11.48 / 29 = - 0.3958620

m2 = - 122.735 / 22.48 = - 5.4597419

Hence,

- 0.3958620 * - 5.4597419 = 2.16

Answer:

Probably 4

Explanation:

Answer:

[tex]Q'_H=1065kJ/min[/tex]

Explanation:

From the question we are told that

Heat Remove rate Q_o= 750 kJ/min

Power Draw P=5.25

a)Generally the coefficient of performance (COP) of an air conditioner is mathematically given as

[tex]COP=\frac{Q_o}{P}[/tex]

[tex]COP=\frac{750kJ/min}{5.25kw}[/tex]

Where

[tex]750kJ/min=12.5kJ/sec[/tex]

[tex]COP=\frac{12.5kJ/sec}{5.25kw}[/tex]

[tex]COP=2.38[/tex]

b)Generally the equation for power is mathematically represented as

[tex]P=Q_H-Q_o[/tex]

[tex]P+Q_o=Q_H[/tex]

[tex]Q_H=P+Q_o[/tex]

[tex]Q_H=5.25+12.5[/tex]

[tex]Q_H=17.75kW[/tex]

Generally rate of heat transfer to the outside air is mathematically given as

[tex]Q'_H=17.75*60[/tex]

[tex]Q'_H=1065kJ/min[/tex]

Answer:

the action or process of distributing things or people over a wide area.

"the dispersal of people to increasingly distant suburbs"

the splitting up of a group or gathering of people, causing them to leave in different directions.

"the dispersal of the crowd by mounted police"

the splitting up and selling off of a collection of artifacts or books.

"the dispersal of the John Willett Collection"

Explanation:

Answer:

she rode for 166.66 seconds , which is about 2 minutes and 47 seconds

Explanation:

We use the kinematic equation that relates initial and final velocities with time and distance travelled that is shown below:

[tex]distance=\frac{(v_i+v_f)*t}{2}[/tex]

which in our case gives:

[tex]distance=\frac{(v_i+v_f)*t}{2}\\500=\frac{(0+6)*t}{2}\\500=3*t\\t=\frac{500}{3} \,s\\t\approx 166.66\,sec[/tex]

which reduced to minutes gives 2 minutes and approximately 47 seconds

Answer:

The man is on the verge of having a heart attack or a stroke.

Explanation:

If he has a family history of coronary (heart) disease, it means it could normally affect. Normally here means without anything aggravating it. It's already in his lineage so he could have it.

Now, he's past middle age - he's 45. He's past the growing stages of life. His organs are fully developed herefore.

Now also, he suffers from Type 2 diabetes. Although this is sometimes milder than Type 1 diabetes, it increases the risk of having a heart disease or a stroke!

Soda, especially sweetened one, is not to be taken too often because it can cause Diabetes Mellitus. For a diabetes patient, this should be a "no-go-area". Taking this constantly (everyday at work) will now put this 45-year-old man in harm's way.

He is no more at risk of having complications but already on the path to a heart disease or a stroke.

Answer:

1. 75 N

2. 6.8351 N

3. 700 N

Explanation:

1. Determination of the weight of the bowling ball:

Mass (m) = 7.5 kg

Acceleration due to gravity (g) = 10 m/s²

Weight (W) =?

Weight = mass × acceleration due to gravity

W = m × g

W = 7.5 × 10

W = 75 N

2. Determination of the weight of the object.

Mass (m) = 683.51 g

Weight (W) =?

We'll begin by converting 683.51 g to kg. This can be obtained as follow:

1000 g = 1 Kg

Therefore,

683.51 g = 683.51 g × 1 Kg / 1000 g

683.51 g = 0.68351 Kg

Thus, 683.51 g is equivalent to 0.68351 Kg.

Finally, we shall determine the weight of the object as follow:

Mass (m) = 0.68351 Kg

Acceleration due to gravity (g) = 10 m/s²

Weight (W) =?

Weight = mass × acceleration due to gravity

W = m × g

W = 0.68351 × 10

W = 6.8351 N

3. Determination of the weight of the KHS student.

Mass (m) = 154 lb

Weight (W) =?

We'll begin by converting 154 lb to Kg. This can be obtained as follow:

2.2 lb = 1 Kg

Therefore,

154 lb = 154 lb × 1 Kg / 2.2 lb

154 lb = 70 kg

Thus, 154 lb is equivalent to 70 kg.

Finally, we shall determine the weight of the KHS student as follow:

Mass (m) = 70 Kg

Acceleration due to gravity (g) = 10 m/s²

Weight (W) =?

Weight = mass × acceleration due to gravity

W = m × g

W = 70 × 10

W = 700 N

Answer:

(a) θ = 20°

(b) Time Delay = 2.84 s

Explanation:

(a)

This is the case of the projectile motion. In projectile motion, for the same launch speed, the range of a projectile is the same for the complimentary launch angles. Hence, the snowball will have the same range when launched at 70°, at an angle of:

[tex]\theta = 90^{0} - 70^{0}[/tex]

θ = 20°

(b)

The time of flight of snowball can be found by the following formula:

[tex]T = \frac{2\ u\ Sin \theta}{g}[/tex]

where,

T = Time of flight = ?

u = launch speed = 23.3 m/s

g = acceleration due to gravity = 9.81 m/s²

For θ = 70° :

[tex]T_{70} = \frac{(2)(23.3\ m/s)Sin70^{0}}{9.81\ m/s^{2}}[/tex]

T₇₀ = 4.46 s

For θ = 20° :

[tex]T_{20} = \frac{(2)(23.3\ m/s)Sin20^{0}}{9.81\ m/s^{2}}[/tex]

T₂₀ = 1.62 s

Therefore, the time delay can be calculated as follows:

[tex]Time\ Delay = T_{70} - T_{20}\\Time\ Delay = 4.46\ s - 1.62\ s\\[/tex]

Time Delay = 2.84 s

A. The angle at which the second ball should be thrown is 20°

B. The delay time between the two throws is 2.83 s

A. Determination of the angle at which the second ball should be thrown

From the question given above, we were told that:

The first ball is thrown at angle of 70°. Both balls covers the same range.

From the above data, the angle at which the second ball should be thrown will be = 90 – 70 = 20°

B. How to determine the delay time between the two throws I. Determination of the time of flight at angle 70°Initial velocity (u) = 23.3 m/sAcceleration due to gravity (g) = 9.8 m/s²Angle (θ) = 70°Time of flight (T) =?

T = 2uSineθ / g

T = (2 × 23.3 × Sine 70) / 9.8

T = 4.45 s

II. Determination of the time flight at angle 20°Initial velocity (u) = 23.3 m/sAcceleration due to gravity (g) = 9.8 m/s²Angle (θ) = 20°Time of flight (T) =?

T = 2uSineθ / g

T = (2 × 23.3 × Sine 20) / 9.8

T = 1.62 s

III. Determination of the delay time Time of flight for 70° = 4.45 sTime of flight for 20° = 1.62 sDelay time =?

Delay time = 4.45 – 1.62

Delay time = 2.83 s

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Answer:

radio waves

Explanation:

Radio waves are used for communication such as television and radio. Radio waves are transmitted easily through air. They do not cause damage if absorbed by the human body, and they can be reflected to change their direction. These properties make them ideal for communications.

Answer:

The answer is radio waves.

Explanation:

I took AP EX quiz.

Answer:

heat given , nature of body, and temperature rise

Answer : 10.35 m/s

Explanation

Answer:

KE = 0.262 J

Explanation:

given data

rifle with mass Mr = 2.57 kg

bullet with mass Mb = 3.65 g

velocity relative to the ground Vb = 318.4 m/s

solution

we get here final KE of rifle that is express as

KE = 0.5 × Mr × (Vr)² ..............1

here Vr is

Mb × Vb = Mr × Vr .........2

put here value

3.65 × [tex]10^{-3}[/tex] × 318.4 = 2.57 × Vr

Vr = 0.452 m/s

now put value in eq 1 we get

KE = 0.5 × 2.57 × (0.452)²

KE = 0.262 J

Answer:

[tex]E = (0.56 \times 10^8 ) r \ \ N/c[/tex]

Explanation:

Given that:

[tex]\rho_o = (10^{-3} ) \ c/m^3[/tex]

R = (0.1) m

To find the electric field for r < R by using Gauss Law

[tex]{\oint}E^{\to}* da^{\to} = \dfrac{Q_{enclosed}}{\varepsilon_o} --- (1)[/tex]

For r < R

[tex]Q_{enclosed}=(\rho) ( \pi r^2 ) l[/tex]

[tex]E*(2 \pi rl)= \dfrac{\rho ( \pi r ^2 l)}{\varepsilon_o}[/tex]

[tex]E= \dfrac{\rho ( r)}{2 \varepsilon_o}[/tex]

where;

[tex]\varepsilon_o = 8.85 \times 10^{-12}[/tex]

[tex]E= \dfrac{10^{-3} ( r)}{2 (8.85 \times 10^{-12})}[/tex]

[tex]E= \dfrac{10^{-3} ( r)}{2 (8.85 \times 10^{-12})}[/tex]

[tex]E = (0.56 \times 10^8 ) r \ \ N/c[/tex]

Answer:

a. 4.733 × 10⁻¹⁹ J = 2.954 eV b i. yes ii. 0.054 eV = 8.651 × 10⁻²¹ J

Explanation:

a. Find the energy of the incident photon.

The energy of the incident photon E = hc/λ where h = Planck's constant = 6.626 × 10⁻³⁴ Js, c = speed of light = 3 × 10⁸ m/s and λ = wavelength of light = 420 nm = 420 × 10⁻⁹ m

Substituting the values of the variables into the equation, we have

E = hc/λ

= 6.626 × 10⁻³⁴ Js × 3 × 10⁸ m/s ÷ 420 × 10⁻⁹ m

= 19.878 × 10⁻²⁶ Jm ÷ 420 × 10⁻⁹ m

= 0.04733 × 10⁻¹⁷ J

= 4.733 × 10⁻¹⁹ J

Since 1 eV = 1.602 × 10⁻¹⁹ J,

4.733 × 10⁻¹⁹ J = 4.733 × 10⁻¹⁹ J × 1 eV/1.602 × 10⁻¹⁹ J = 2.954 eV

b. i. Is this energy enough for an electron to leave the atom

Since E = 2.954 eV is greater than the work function Ф = 2.9 eV, an electron would leave the atom. So, the answer is yes.

ii. What is its maximum energy?

The maximum energy E' = E - Ф = 2.954 - 2.9

= 0.054 eV

= 0.054 × 1 eV

= 0.054 × 1.602 × 10⁻¹⁹ J

= 0.08651 × 10⁻¹⁹ J

= 8.651 × 10⁻²¹ J

Answer:

Since there are hundreds of nails, instead of puncturing your skin the nails actually support you.

Explanation:

If you step on the point of a nail, your foot exerts a tremendous amount of pressure on the nail's tiny point. As a result, the point can go straight through your foot. But a bed of nails has lots of points that are close together -- there's a lot of surface area for the body to cover. Hundreds of nails support the weight of your body instead of just one. Typically, your body doesn't exert enough pressure on any one nail for it to break the skin. You can even place a second bed on top of you and break a cinderblock on it. The resulting force is distributed over all of the nails, so you shouldn't be injured.

The impact force will be less because of the pressure is equally distributed over the body of man. The nails will not puncture his skin.

What is pressure?

The pressure of any object is given by the force acting per unit area. When the contact area is less, the object will penetrate.

If one steps on the point of a nail, his foot exerts a tremendous amount of pressure on the nail's contact point. As a result, it will penetrate into the foot. In case of a bed of nails, many nail points placed close together. The surface area for the body to make contact is increased.
Then, hundreds of nails now will support the weight of his body.

Thus, the impact force will be less because of the pressure is equally distributed over the body of man. The nails will not puncture his skin.

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Answer:

Increasing the force acting on an object will increase its acceleration

Explanation:

The force acting on an object is given by the formula as follows :

F = ma

Where

m is mass and a is acceleration of the object

It can be seen that the force and the acceleration are directly proportional to each other.

It means if we increase the acceleration of the object, the force will increase and vice versa.

Hence, the correct option is (c) "Increasing the force acting on an object will increase its acceleration".

Answer:

i think Increasing the force acting on an object will increase its acceleration

Explanation:

Answer:

See explanation below.

Explanation:

The internal energy (kinetic energy) of the milk particles increases thus warming the milk up, while the internal energy of the coffee particles reduce their initial average speed as they are imparting energy to the slow milk particles.

Answer:

44.5s ; 22.64 m/s

Explanation:

The motion of the truck could be separated into 3 different phases :

First :

Time of motion :

Initial Velocity, u = 0 ; final velocity, v = 29 m/s

Acceleration, a = 2 m/s²

Recall: acceleration = change in velocity / time

Time = change in velocity / acceleration

Time = (29 - 0) / 2 = 14.5 second

Distance traveled = ((29 + 0) /2) * 14.5 = 210.25 m

Second :

Time = 25 seconds at constant speed

29 m/s for 25 seconds

v*t = 29 * 25 = 725 m

Third:

5 seconds before coming to rest

((29 + 0) /2) * 5

14.5 * 5 = 72.5 m

A.)

Length of journey = (14.5+ 25 + 5) = 44.5 seconds

B.)

Average velocity = total distance / total time taken

Average velocity = (210.25 + 725 + 72.5) / 44.5

= 1007.75 / 44.5

= 22.646067

= 22.64 m/s

Answer:

Positive charge is attracted to the neutral object.

Explanation:

Recall ; Like charges repel, unlike charges attract. This phrase simply means (positive (+) is attracted to negative (-ve) and vuc versa while both positive, positive and negative, negative charge repel.

For a neutral object. The quantity of positive charge equals the quantity of negative charges. This simply means a neutral object contains charges as well, which are usually scattered or randomly aligned.

Therefore, when a positive charge is brought near a neutral body, the order of alignment of the charges change, with the negative charge all moving towards the direction of the positively charged body and the positive charges in the neutral body aligning in the opposite direction.

The charge will be attracted.

Understanding the force between charges.

As you may know, opposite charges attract (and equal charges repel).

So, when you put a positive charge near a neutral material, all the negative charges in the material will move towards the surface of the material closer to the positive charge (and the positive charges in the material will move away).

Now the charge in the material is not homogeneous, so the positive charge will see a negatively charged surface near it, and it will be attracted to that surface.

Thus we can conclude that as a positive charge is brought near a neutral, insulating piece of material, the charge will be attracted towards it.

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